Azzera filtri
Azzera filtri

Short code for the expression

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Tino
Tino il 1 Mag 2019
Commentato: Guillaume il 1 Mag 2019
h =2;
P = [1, 4, 5, 7];
a1 = (1-h)* 1 + h * P(:, 1);
a2 = (1-h) * a1 + h * P(:, 2);
a3 = (1-h) * a2 + h * P(:, 3);
a4 = (1-h) * a3 + h * P(:, 4);
disp(a1) = 1
disp(a2) = 7
disp(a3) = 3
disp(a4) = 11
  2 Commenti
Tino
Tino il 1 Mag 2019
Please I will appreciate the answer to this question
thanks in advance
Guillaume
Guillaume il 1 Mag 2019
To what question? You haven't asked anything, just given us some code with no explanation nor context.

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Risposta accettata

madhan ravi
madhan ravi il 1 Mag 2019
Modificato: madhan ravi il 1 Mag 2019
a = num2cell( (1-h) * repmat( (1-h) * 1 + h * P(1), 1, 4) + h * P ) ;
[a1, a2, a3, a4] = deal( a{:} )
  6 Commenti
Tino
Tino il 1 Mag 2019
Modificato: Tino il 1 Mag 2019
sorry the right figure is the one below. sorry for giving wrong computation
Can you help me with the short code to gives the following answers for h = any number for instance
when h = 1
1
4
5
7
when h = 2
1
7
7
3
when h = 3
1
10
1
13
thanks in advance
Guillaume
Guillaume il 1 Mag 2019
In your question, you told us than when h = 2, a = [1 7 3 11] (for P = [1, 4, 5, 7]) and this is the answer that my code produces. I have no idea how you get your new answer. It doesn't match the formula you've posted.

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R2019a

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