How to execute multiple optimized values for x according to n, using fmincon

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Maheen Fazal on 17 May 2019
Commented: Maheen Fazal on 17 May 2019
Hello, kindly help me in finding n optimal values for x (x is a vector not single valued).
e.g. i have the main code
function Rsum Simple(x)
global n
R=20*1000;
Rn =x*R;
Rsum=sum(Rn);
end
by using fmincon i am optimizing x
clear all
clc
global n
n_vec=2:2:6;
throughput=[];
for n=n_vec
initial_guess=0.00002;
x0=initial_guess;
lb=0;
ub=0.7;
A = [];
b = [];
Aeq=[];
Beq=[];
[x,fval]= fmincon(@(x) Simple(x),x0,A,b,[],[],lb,ub);
max=-(fval);
throughput=[throughput max];
end
after executing first attempt i want to get 2 optimized values of x,in 2nd i need 4 optimized values and in 3rd time x=6, but i dont know how to execute it. can any body help me out to find multiple values of x(with respect to n).??

Titus Edelhofer on 17 May 2019
Edited: Titus Edelhofer on 17 May 2019
Hi,
there are a couple of things I don't understand: you say "x is a vector"? But you always start with x0=initial_guess, which is a scalar. Perhaps this is the first change you would need to do:
x0 = repmat(initial_val, n, 1);
to make x0 a vector.
Second, your objective function is strange. Variable S is not used? x = [0...0] is the solution for the function you wrote.
Titus
Maheen Fazal on 17 May 2019
Sorry it was by mistakenly wrriten, okay Sir will changes in initial guess.

Maheen Fazal on 17 May 2019
Edited: Maheen Fazal on 17 May 2019
just let me know if i have to find n optimal values for x then how could i find?

Maheen Fazal on 17 May 2019
can i also change uper and lower bounds accordingly?
Maheen Fazal on 17 May 2019
for i=1:n
[x(i),fval(i)]= fmincon(@(x) Simple(x),x0(i,:),A,b,[],[],lb(i,:),ub(i,:),@constraint);
end
is this a right way to execute?