Please anyone help me with the error!
3 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
Risposta accettata
Più risposte (1)
KSSV
il 28 Mag 2019
potential = double(potential) ;
fprintf('the potential difference is = %f\n',potential) ;
Your variable potential is in syms...convert it to double. Read about double.
3 Commenti
Vedere anche
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!