solving pohlhausen equation,how I can write true function?
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I write this function for solve pohlhausen equation.(T''+Pr/2 F T'=0 ) That F is output of blasius equation( 2F'''+FF''=0).but my code has error.how I can write true function?
function [Tetadot,fdot]=pohlhausen(eta,Teta,f);
fdot=blasius(eta,f);
Tetadot(1)=Teta(2);
Tetadot(2)=-(0.7/2)*f(1)*Teta(2);
Tetadot=Tetadot';
function fdot=blasius(eta,f);
fdot(1)=f(2);
fdot(2)=f(3);
fdot(3)=-(1/2)*f(1)*f(3);
fdot=fdot';
end
end
2 Commenti
mahdi etminan
il 6 Giu 2019
Torsten
il 6 Giu 2019
You'll have to solve both equations (Blasius and Pohlhausen) together, not one after the other.
Risposte (1)
Star Strider
il 6 Giu 2019
If you have the Symbolic Math Toolbox, let it do the programming for you:
% % 2F'''+FF''=0
% % T''+Pr/2 F T'=0
syms F(t) Pr T(t) t Y
Blasius = 2*diff(F,3)+F*diff(F,2) == 0;
Polhausen = diff(T,2) + Pr/2 * F * diff(T) == 0;
[VF,Sbs] = odeToVectorField(Blasius, Polhausen) % Vector Field Representation & Substitutions
polhfcn = matlabFunction(VF, 'Vars',{t,Y,Pr}) % Anonymous Function
varcell = sym2cell(Sbs); % Cell Array Of Substitutions
varstr = sprintfc('%s',[varcell{:}]); % Cell Array Of Substitution Strings (For ‘legend’ Or Other Uses), Can Also Use The ‘compose’ Function
producing:
polhfcn = @(t,Y,Pr) [Y(2);Pr.*Y(2).*Y(3).*(-1.0./2.0);Y(4);Y(5);Y(3).*Y(5).*(-1.0./2.0)];
and other information.
You would define a value for ‘Pr’ in your workspace, then use the function (in ode45, for example, although I have no idea what solver is most appropriate here):
[t,y] = ode45(@(t,Y)polhfcn(t,Y,Pr), tspan, ics);
Check to be sure I entered the equations correctly. I believe I did, although it is always appropriate to check.
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