Loop Confusion while referencing random values

I have a code that

1. randomly generates values between 0 and1
2. The value is then referenced into percent weight table and generates an integer between 1 and 10
3. it then states whether the integer generated is located in set1 set2 or set3

I would like this code to loop and continue producing the random values between 0 and 1 until the integer generated in step 2 is located in set1

Sets 1 2 and 3 do not contain matching values, but do contain all values 1-10

Step 2 only generates values between 1 and 10, so every integer generated is located in only one of the 3 sets of values

Value = rand;
Low = Value<=percentweight; %This compares the generated value to the table
value2 = Table{end-sum(Low),integer}; %This utilizes the comparison to select the correct integer for the generated value
1 = sum(value2 == Set1); %1,2,and3 compare the integer selected to three separate sets of values
2 = sum(value2 ==Set2);
3 = sum(value2 == Set3);

[Geoff Hayes]

Jillyn - what is your intent with the code

1 = sum(value2 == Set1);

Are you trying to compare the value to one? Or are you trying to assign the result to a variable? Please note that variable names must begin with a letter (see naming variables for details). You may want to rename the variables as

inSet1 = sum(value2 == Set1); %1,2,and3 compare the integer selected to three separate sets of values
inSet2 = sum(value2 == Set2);
inSet3 = sum(value2 == Set3);

I'm not sure where in your code you update the three different sets, but you probably want a loop something like the following

maxIterations = 1000;
for k = 1:maxIterations
    Value = rand;
    Low = Value<=percentweight; %This compares the generated value to the table
    value2 = Table{end-sum(Low),integer}; %This utilizes the comparison to select the correct integer for the generated value
    inSet1 = sum(value2 == Set1); %1,2,and3 compare the integer selected to three separate sets of values
    inSet2 = sum(value2 == Set2);
    inSet3 = sum(value2 == Set3);
    if inSet1
        break;
    end
end

So we exit the loop if the integer is in the first set (i.e. inSet1 is true).