How to fill wing movement in 3d?

Hi,

I have a n-by-3 matrix of flapping wing tip path and a stationary base point (zeros(3,n)) - attached as 'wingtip.m'.

I want to use the 'fill3' function but I don't really understand how to use it in here.

I wish to fill the path in which the wing passes threw time.

The BAD way I did it so far is:

figure; hold on;
for i = 1:length(AA) % This is how the matrix in 'wingtip.m' is called
    wing(1,1:3) = AA(i,1:3);
    wing(2,1:3) = [0 0 0];
    plot3(wing(:,1),wing(:,2),wing(:,3),'b','linewidth',10);
end

[darova]

DOesn't look like wing

load('wingtip.mat')
fill3(AA(:,1), AA(:,2), AA(:,3),'r')

[Ziv Kassner]

You missed the wing base...

[darova]

What does it mean?

[Ziv Kassner]

The wing that moves from t0 to t1 creates a triangle between AA(1,1:3), AA(1,4:6) and AA(2,1:3). This is the area I would like to use 'fill3' on. If you'll do it for an hellicopter, you will see a disk like shape from above (the aerea between blade tip and base, in time).

[KSSV]

What coodinates correspond to wing?

[Ziv Kassner]

AA(:,1:3) are wing tip trajectory, AA(:,4:6) is wing base that is stationary.

Answer 1

[Ziv Kassner]

Just made it happen:

for i = 1:length(AA)-1
    fill3([AA(i,1);AA(i,4);AA(i+1,1)],...
        [AA(i,2);AA(i,5);AA(i+1,2)],...
        [AA(i,3);AA(i,6);AA(i+1,3)],'r','edgecolor','none')
    hold on;
end
axis equal; grid on;

Thank you

[darova]

no need for loop

x = AA(:,1);
y = AA(:,2);
z = AA(:,3);
h = surf([x x*0]', [y y*0]', [z z*0]');

alpha(h,0.5)
set(h,'EdgeColor','none')
set(h,'FaceLighting','phong',...
      'AmbientStrength',0.5)
light('Position',[1 0 0],'Style','infinite');

#EDITED

[Ziv Kassner]

Even better,

Thanks,

Ziv

Answer 2

[KSSV]

This is what you are looking for?

load 'wingtip.mat'
t = AA(:,1:3)  ; 
wing = AA(:,4:6) ; 
patch(t(:,1),t(:,2),t(:,3))