calculating hourly means of a matrix
2 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
I have a dataset in the following format:
dd = datenum('2009-04-17 02:00');
ddend = datenum('2009-11-24 12:27');
Day = dd:(1./24./60):ddend;
time = datevec(Day);
data = rand(length(time),12);
Where time refers to the time (in minutely intervals) and data refers to a matrix of data points. I would like to find the best possible way of calculating the hourly means of each column of the matrix (i.e. mean of every 24 rows in each individual column). How would I achieve this, by taking into consideration the time variable?
0 Commenti
Risposta accettata
Jan
il 27 Ago 2012
limit = floor(length(time) / 60) * 60;
data_hour = reshape(data(1:limit), 60, []);
data_mean = mean(data_hour, 1);
0 Commenti
Più risposte (1)
Andrei Bobrov
il 27 Ago 2012
other variant
[c,c,c] = unique(time(:,1:4),'rows');
s{2} = kron((1:size(data,2))',ones(size(data,1),1));
s{1} = kron(ones(size(data,2),1),c);
result = accumarray(s,data(:),[],@mean);
1 Commento
Venkata
il 11 Mag 2017
Dear Andrei Bobrov,
Could you please elaborate on your code. I want to reshape hourly mean data which is in vector form to a matrix, but there might be some data (hourly values) missing. When I tried your code, I got an error related to array size. Mine is a large array with 210888 rows.
Thank you.
Vedere anche
Categorie
Scopri di più su Time Series in Help Center e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!