Matrix interpolation in the direction of the third dimension

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Hello!
I would like to perform matrix (n x n) interpolation in the direction of the third dimension which is frequency (1 x N), in a way to obtain intermediate matrices which are the interpolated ones. In my case I need to perform quadratic interpolation method which is not provided in interp1, and the use of polyfit together with polyval needs vectors while I have matrices. any ideas how can I proceed? Thank you very much!
  3 Commenti
Jan
Jan il 19 Giu 2019
@Ano: Please mention, what your inputs are. You can use polyfit to get the scaling factors for each matrix.
John D'Errico
John D'Errico il 24 Giu 2019
Please don't add answers just to respond to an answer. Note that multiple people have made COMMENTS. Learn to use them.

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Risposte (1)

Gert Kruger
Gert Kruger il 19 Giu 2019
Here is my attempt at answering your question. I imagine that there are N matrices each with size nxn.
Example matrices:
%%
n = 10; %Matrix size
N = 5; %Number of matrices
%% Generate example matrices
for count = 1:N
CM{count} = rand(n) ; %CM Cell array matrices
end
Then we fit quadratic functions along the third dimension.
%% Generate fits along the third dimension
temp_ar = zeros(1, N);
for x = 1:n
for y = 1:n
for z = 1:N
temp_ar(z) = CM{z}(x, y);
end
Cfit{x, y} = fit( (1:N)', temp_ar', 'poly2');
end
end
Interpolation is achieved by evaluating the fitted functions:
%% Output matrix generation
%For example output matrix, A, must be 'halfway' between 2nd and 3rd input matrices
A = zeros(n);
z = 2.5; %Evaluation depth
for x = 1:n
for y = 1:n
A(x, y) = Cfit{x, y}(z);
end
end
We can test the output matrix, by using the norm:
norm(CM{2} - A)
norm(CM{3} - A)
norm(CM{5} - A)
Note, that the measure of the difference for the first two is less than for the last one, because the matrix A slice is 'further away' from that depth.
  3 Commenti
Gert Kruger
Gert Kruger il 27 Giu 2019
Ano,
the matrices A in my proposed answer is generated from the CM matrices. In my case, when z=1, A=CM{1} and when z=2 then A=CM{2}.
I don't know what you mean by inserted. Do you instead mean that there are new matrices (sample points) which need to be sorted into the CM matrix list?
Ano
Ano il 28 Giu 2019
First, thank you very much for your reply, I am grateful for that.
yes, which means that the obtained matrix A at z= 2.5 from your example need to be added into the final version of CM, therefore if I have at the beginning CM defined for 5 frequency samples, and I computed A let say for two additional intermediate samples (i.e., z= 2.5, and z =3.5) my final CM must be defined for 7 samples including the newly interpolated values represented by matrix A. Any suggestions?!

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