bitset error for uint64
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Jason Palmer
il 19 Giu 2019
Commentato: Jason Palmer
il 19 Giu 2019
There seems to be a problem with the bitset function for uint64. Here is a simple example:
>> d = 38124631952277504;
>> dec2bin(d)
ans =
'10000111011100100010011010011000101101010100000000000000'
>> dec2bin(d+1)
ans =
'10000111011100100010011010011000101101010100000000000000'
>> dec2bin(bitset(d,1,'uint64'))
ans =
'10000111011100100010011010011000101101010100000000000000'
>> dec2bin(bitset(d,2,'uint64'))
ans =
'10000111011100100010011010011000101101010100000000000000'
>> dec2bin(bitset(d,3,'uint64'))
ans =
'10000111011100100010011010011000101101010100000000000000'
>> dec2bin(bitset(d,4,'uint64'))
ans =
'10000111011100100010011010011000101101010100000000001000'
>> dec2bin(d+8)
ans =
'10000111011100100010011010011000101101010100000000001000'
So the bits only change successfully from 4th bit on, but fail to set fo the first three bits. This makes no sense that I can see and seems to be a serious error in Matlab.
Any help would be appreciated. Or advice on how to alert Matlab engineers.
Thanks,
Jason
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Risposta accettata
Utkarsh Belwal
il 19 Giu 2019
Modificato: Utkarsh Belwal
il 19 Giu 2019
Read the documentation of dec2bin, it is written that if number is greater than flintmax then it might not work properly. In your case d is greater than flintmax.
Più risposte (1)
Steven Lord
il 19 Giu 2019
>> d = 38124631952277504;
>> dec2bin(d)
ans =
'10000111011100100010011010011000101101010100000000000000'
>> dec2bin(d+1)
ans =
'10000111011100100010011010011000101101010100000000000000'
d is a double precision array, and the distance from d to the next largest representable number is greater than 1. In fact, it's 8.
>> eps(d)
ans =
8
>> isequal(d, d+1) % returns true
If you want to work with integer data that's this large, I recommend working with integer data rather than double. Make your d variable an uint64 from the beginning. This will also allow you to see the change you're making with each bitset call without needing dec2bin.
>> du = uint64(38124631952277504)
du =
uint64
38124631952277504
>> du1 = bitset(du, 1)
du1 =
uint64
38124631952277505
>> du2 = bitset(du, 2)
du2 =
uint64
38124631952277506
>> du3 = bitset(du, 3)
du3 =
uint64
38124631952277508
>> du4 = bitset(du, 4)
du4 =
uint64
38124631952277512
If you do need to check the bits explicitly, use bitget. It's vectorized so you can get all the bits at once. If you need it as a char vector, you can combine bitget with sprintf.
bitget(du, 64:-1:1)
bitget(du1, 64:-1:1)
sprintf('%d', bitget(du4, 64:-1:1))
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