MATLAB Answers

Too many output argument

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Yash Mistry
Yash Mistry on 4 Jul 2019
Commented: madhan ravi on 19 Jul 2019
Hi, I am trying to plot a 3D gyroid using the following code
fimplicit3(@(x,y,z) sin(x).*cos(y) + sin(y).*cos(z) + sin(z).*cos(x))
but it shows me too many output argument as the error. Also a bank 3D plot opens up with only X Y Z axis.
Can you help?

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Walter Roberson
Walter Roberson on 5 Jul 2019
What happened when you tried the dbstop if warning ?
Yash Mistry
Yash Mistry on 5 Jul 2019
function defaulterrorcallback(~, evt)
% The default value for ErrorCallback properties.
% Copyright 2009-2017 The MathWorks, Inc.
[id, msg] = matlab.graphics.internal.prepareDefaultErrorCallbackWarning(evt);
stack = dbstack('-completenames');
if (size(stack,1) == 1)
warningstatus = warning('OFF', 'BACKTRACE');
warning(id, msg);
warning(warningstatus);
else
warning(id, msg);
end
end
Warning from defaulterrorcallback (line 9)
warning(id, msg);
Sorry for this messy reply, I dont really understand but i have copy pasted whatever it showed me on my matlab.
Thank you so much.
Walter Roberson
Walter Roberson on 5 Jul 2019
At that point it would be useful to see the contents of the stack variable.

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Answers (1)

SaiDileep Kola
SaiDileep Kola on 19 Jul 2019
fimplicit3(@(x,y,z) sin(x).*cos(y) + sin(y).*cos(z) + sin(z).*cos(x))
Hi,
This function doesn’t show any error and gives as gyroid as shown in figure, store it to a handle as
fh = fimplicit3(@(x,y,z) sin(x).*cos(y) + sin(y).*cos(z) + sin(z).*cos(x));
Before doing this clear all variables stored in your workspace, change settings on MATLAB to default
Plot looks like

  2 Comments

Walter Roberson
Walter Roberson on 19 Jul 2019
The warnings the user was getting suggests there is some shadowed function or a corrupt MATLAB installation. They were already doing the fimplicit3.
madhan ravi
madhan ravi on 19 Jul 2019
Second sir Walter’s comment.

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