Why the conversion of filename to char? If it's not already a char array what is it?
You should always check the return value of fopen. Clearly, it failed to open the file. The most common reason is that your current directory is not where the file is. And the easiest way to fix that is to use absolute paths
folder = 'C:\somewhere\somefolder';
[fid, errmsg] = fopen(fullfile(folder, char(filename)));
assert(fid > 0, 'Failed to open file, error was: %s', errmsg);
Also, rather than clearing the a variable, which has a meaningless name, simply reuse your region variable, which is a much better name anyway:
region = fscanf(fid,'%g',inf);
fclose(fid);
region = reshape(region, nx, ny);