solve a system of equations symbolically with R2018a

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Katy Skillings
Katy Skillings il 16 Lug 2019
Commentato: Walter Roberson il 17 Lug 2019
>> eqn1='(Fa0*x1)/0.1*(9.05*(1-x1))*(27.8-9.05*x1))==3785'
eqn1 =
'(Fa0*x1)/0.1*(9.05*(1-x1))*(27.8-9.05*x1))==3785'
>> eqn2='(Fa0*(x2-x1))/0.1*(9.05*(1-x2))*(27.8-9.05*x2))==3785'
eqn2 =
'(Fa0*(x2-x1))/0.1*(9.05*(1-x2))*(27.8-9.05*x2))==3785'
>> eqn3='(Fa0*(0.95-x2))/0.1*(9.05*(1-0.95))*(27.8-9.05*0.95))==3785'
eqn3 =
'(Fa0*(0.95-x2))/0.1*(9.05*(1-0.95))*(27.8-9.05*0.95))==3785'
>> solT=solve(eqn1,eqn2,eqn3,x1,x2,Fa0)
Error using solve>getEqns (line 418)
List of equations must not be empty.
Error in solve (line 226)
[eqns,vars,options] = getEqns(varargin{:});

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Risposte (1)

Walter Roberson
Walter Roberson il 16 Lug 2019
You are using R2018b or later. solve() no longer accepts character vectors for equations.
Furthermore, each of your equations has an extra ) before the ==
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Katy Skillings
Katy Skillings il 17 Lug 2019
Thank you. I attempted solving another way and got this answer as well but was intimidated by the lengthy answer. What is vpa?

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