How to pre-allocate a struct in Matlab
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Hamed Bolandi
il 19 Lug 2019
Commentato: Hamed Bolandi
il 19 Lug 2019
I want to pre-allocate stuct e1 and struct e3 in the following loop. I would be thankfull if someone can help.
clc;
clear;
close all;
x=[-30;-25;-20;20;25;30;30;25;20;-20;-25;-30];
y=[-25;-25;-25;-25;-25;-25;25;25;25;25;25;25];
i=x(1:end);
j=y(1:end);
M=[i,j];
s.x=[];
s.y=[];
c=repmat(s,12,1);
c(1).x=M(1,1);
c(1).y=M(1,2);
c(2).x=M(2,1);
c(2).y=M(2,2);
c(3).x=M(3,1);
c(3).y=M(3,2);
c(4).x=M(4,1);
c(4).y=M(4,2);
c(5).x=M(5,1);
c(5).y=M(5,2);
c(6).x=M(6,1);
c(6).y=M(6,2);
c(7).x=M(7,1);
c(7).y=M(7,2);
c(8).x=M(8,1);
c(8).y=M(8,2);
c(9).x=M(9,1);
c(9).y=M(9,2);
c(10).x=M(10,1);
c(10).y=M(10,2);
c(11).x=M(11,1);
c(11).y=M(11,2);
c(12).x=M(12,1);
c(12).y=M(12,2);
for i=1:27
j=c(2);
k=c(4);
l=c(7);
o=c(10);
e3(i,:)=[j;k;l];
for i=1:3:25
o=c(10);
e1(i,:)=o;
end
for i=2:3:26
o=c(11);
e1(i,:)=o;
end
for i=3:3:27
o=c(12);
e1(i,:)=o;
end
for i=4:6
k=c(5);
e3(i,:)=[j;k;l];
end
for i=7:9
k=c(6);
e3(i,:)=[j;k;l];
end
for i=10:18
l=c(8);
e3(i,:)=[j;k;l];
end
for i=13:15
k=c(5);
e3(i,:)=[j;k;l];
end
for i=16:18 %#ok<*FXSET>
k=c(6);
d3(i,:)=[j;k;l];
end
for i=19:27
l=c(9);
e3(i,:)=[j;k;l];
for i=22:24
k=c(5);
e3(i,:)=[j;k;l];
end
for i=25:27
k=c(6);
e3(i,:)=[j;k;l];
end
end
e=[e3,e1];
end
4 Commenti
Rik
il 19 Lug 2019
Try to write some comments in your code what it is doing. You are overwriting entries several times without any clear reason. The answer below (zeros(27,3)) will work, but is likely not your problem.
Risposta accettata
Sulaymon Eshkabilov
il 19 Lug 2019
Modificato: madhan ravi
il 19 Lug 2019
Did you mean memory pre-allocation? if so, then
e1=zeros(27,1);
e3=ones(27,3);
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