I do not understand why my code still gives me errors

1 visualizzazione (ultimi 30 giorni)
I'm basically setting a Runge-Kutta of order 4 to solve a sort of 'pred-prey' model. So, my three programs are:
1.
function [t,y]=RK(fun,tspan,y0,n,A,b,c)
h=(tspan(2)-tspan(1))/n;
y(:,1)=y0;
t(1)=tspan(1);
s=length(b);
for j=1:n
$ k(:,1)=feval(fun,t(j),y(:,j));
for i=2:s
k(:,i)=feval(fun,t(j)+c(i)*h,y(:,j)+h*k(:,1:i-1)*A(i,1:i-1)');
end
end
2.
function dy=pred_prey(t,y)
function s=cos(x)
k=1;
a=2/3;
d=4/3;
r(t)=int(s(x^2),x,0,t);
mu(t)=13/20-(3/5)*exp(-(3/x));
dy(1)=(y(1)+k)*r(t)-a*y(1)*y(2);
dy(2)=-mu(t)*y(2)+d*y(1)*y(2);
dy=dy';
3.
function []=driver_pred_prey()
close all
tspan=[0 100];
n=1000;
fun='pred_prey';
y0=[0 -1]';
A=[0 0 0 0; 1/2 0 0 0 ; 0 1/2 0 0; 0 0 1 0];
b=[1/6 1/3 1/3 1/6]';
c=[0 1/2 1/2 1]';
$$ [t,y]=RK('pred_prey', tspan, y0, n, A, b, c);
figure (1)
plot(t, y(1,:), 'k-'), hold
plot(t, y(2,:), 'k-.')
legend('resources',ppl')
figure (2)
plot(y(1,:),y(2,:))
title('orbits)
but I really do not understand what errors there are at $ and $$
  6 Commenti
Jan
Jan il 24 Lug 2019
What about:
% Integral cos2(x) dx = 0.5 * (cos(x)*sin(x) + x)
This is only the part of the messages, which shows where the error is, but not what it is:
  • Error in RK (line 8) k(:,1)=feval(fun,t(j),y(:,j)); (this is the $ line)
  • Error in driver_pred_prey (line 14) [t,y]=RK('pred_prey', tspan, y0, n, A, b, c);
Please post the complete messages.
For the first message:
  • Output argument "dy" (and maybe others) not assigned during call to "pred_prey".
Did you remove the orphaned "function s=cos(x)" as you have been instructed already? Then this message should disappear.
DAVIDE TRONO
DAVIDE TRONO il 24 Lug 2019
function [t,y]=RK(fun,tspan,y0,n,A,b,c)
h=(tspan(2)-tspan(1))/n;
y(:,1)=y0;
t(1)=tspan(1);
s=length(b); %numero di l
for J=1:n
k(:,1)=feval(fun,t(j),y(:,j));
for i=2:s
k(:,i)=feval(fun,t(j)+c(i)*h,y(:,j)+h*k(:,1:i-1)*A(i,1:i-1)');
end
end
code number 1, it is called RK
function dy=pred_prey(t,y)
k=1;
a=2/3;
d=4/3;
f=@(x)cos(x.^2)
r=@(t)integral(f,0,t);
mu=@(t)13/20-(3/5)*exp(-(3/t));
dy(1)=(y(1)+k)*r(t)-a*y(1)*y(2);
dy(2)=-mu(t)*y(2)+d*y(1)*y(2);
dy=dy';
this is the number 2, called pred_prey
function []=driver_pred_prey()
close all
tspan=[0 500];
n=1000;
fun='pred_prey';
y0=[0 -1]';
A=[0 0 0 0; 1/2 0 0 0 ; 0 1/2 0 0; 0 0 1 0];
b=[1/6 1/3 1/3 1/6]';
c=[0 1/2 1/2 1]';
[t,y]=RK(fun, tspan, y0, n, A, b, c);
figure (1)
plot(t, y(1,:), 'k-'), hold
plot(t, y(2,:), 'k-.')
legend('resources','population')
figure (2)
plot(y(1,:),y(2,:))
title('orbits')
and this is the 3rd one, called driver_pred_prey. The second one has been changed so now the syntax should be right but yes, when I try to run the third(which calls the first two) basically I get reported this:
  • Index exceeds the number of array elements (1).
  • Error in RK (line 8)
  • k(:,1)=feval(fun,t(j),y(:,j));
  • Error in driver_pred_prey (line 14)
  • [t,y]=RK(fun, tspan, y0, n, A, b, c);
Those are all the error messages MatLab reports, but I really don't see where is the problem!

Accedi per commentare.

Risposta accettata

Jan
Jan il 24 Lug 2019
Index exceeds the number of array elements (1).
Error in RK (line 8)
k(:,1)=feval(fun,t(j),y(:,j));
After the line:
t(1)=tspan(1);
t is a scalar.
If you run this code:
for J=1:n
k(:,1)=feval(fun,t(j),y(:,j));
another error is expected: The for loop uses an uppercase J as counter, but inside the loop there is a lower case j. Because it is not defined, j is the imaginary unit and cannot be used as index.
If you fix this to for j = 1:n, there is the problem, that t is a scalar and you cannot access t(2).
Maybe you want this instead:
t = linspace(tspan(1), tspan(2), n);
  2 Commenti
DAVIDE TRONO
DAVIDE TRONO il 24 Lug 2019
Well as you said there's no problem when defining
t=linspace(tspan(1),tspan(2),n);
but now a new problem is reported:
  • Index in position 2 exceeds array bounds (must not exceed 1).
(the other two are the same as before). I guess there's just a little mistake with the indexes.
Jan
Jan il 24 Lug 2019
Modificato: Jan il 24 Lug 2019
Again: Please post a complete copy of the error message. The details matter.
In which line does the error occur? There is an index in position 2, which exceeds the limits. This should help you to find and to fix the problem.
With some guessing: The code tries to access y(:,j), but this has not been defined anywhere before. The Runge Kutta code calculates the k 's only, but does not create the values for the actual trajectory.
You find many working Runge-Kutta-codes in the net.

Accedi per commentare.

Più risposte (0)

Categorie

Scopri di più su Programming in Help Center e File Exchange

Prodotti


Release

R2019a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by