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To find the maximum value in a matrix?

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Let me have a 3X3 matrix
6 8 9
7 10 11
21 22 8
How to find the maximum value from this matrix?
  2 Commenti
Jan
Jan il 5 Set 2012
Sorry that I mention the barely obvious, but the answer is 22.
KHOIROM Motilal
KHOIROM Motilal il 17 Mar 2016
Modificato: KHOIROM Motilal il 17 Mar 2016
  • clc
  • close all
  • clear all
  • X=[99 67 65;
  • 63 62 61;
  • 41 40 9];
  • MAX=X(1,1);
  • for i=1:3
  • for j=1:3
  • if MAX<= X(i,j);
  • MAX=X(i,j);
  • end
  • end
  • end
  • disp(MAX)

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Risposta accettata

Michael Völker
Michael Völker il 5 Set 2012
Modificato: Steven Lord il 25 Mar 2020
Starting in R2018b, you can use the following command to find the maximum over all elements in an array A:
M = max(A, [], 'all');
For previous releases, use:
M = max(A(:));
  4 Commenti
Steven Lord
Steven Lord il 11 Dic 2022
The max function's first two inputs are the two matrices whose values you want to compare. If you only want to compute the maximum of one matrix, you need something to use as a placeholder for that second matrix. Otherwise if you wrote something like this, are you asking for the maximum of the elements of a matrix and the value 1 or are you asking for the maximum along the 1st dimension?
max(A, 1)
To break that ambiguity, that syntax is interpreted as the former (the maximum of the elements of A and the value 1) while the following is the latter (the maximum along the 1st dimension.)
max(A, [], 1)

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Più risposte (5)

Azzi Abdelmalek
Azzi Abdelmalek il 5 Set 2012
max(max(A))
  4 Commenti
Jonathan Posada
Jonathan Posada il 20 Feb 2016
This works for the 2D case but if ndims(A)>2, then max(max(A)) will return a matrix. I believe OP wants the maximum element along all dimensions
DGM
DGM il 11 Dic 2022
Not that this is a good idea, but for an arbitrary number of dimensions:
A = rand(100,100,100,10); % a fairly large ND array
% find global maximum of A
maxval = max(A);
for n = 2:ndims(A)
maxval = max(maxval);
end
maxval
maxval = 1.0000
It hasn't been so for quite some time, but in my experience, this iterative approach had a significant speed advantage with larger N-D arrays in older versions (2x-3x as fast as max(A(:)) for the arrays I was using). I don't remember if that advantage still existed in R2012x, but it did in R2009b. In current versions, using vectorization or 'all' are faster for small arrays and roughly equivalent for large arrays. That's on my hardware, so I make no guarantees that it's exactly universal.
Performance aside, it's hard to justify this verbose method over the canonical techniques, if only for the sake of readability.
It's not something I'd recommend, and I doubt that the legacy performance is the typical reason that people gravitate to the approach, but I thought it was interesting to note for old time's sake.

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Tom
Tom il 28 Gen 2020
M = max(A,[],'all') finds the maximum over all elements of A. This syntax is valid for MATLAB® versions R2018b and later.
  2 Commenti
John Doe
John Doe il 31 Gen 2020
This should be upvoted and/or somehow appear closer to the chosen answer, as M = max(A,'all') seems not to work at all in R2018b+ (returning the entire matrix).
M = max(A(:)) seems to work in R2018b+ and presumably universally.
Steven Lord
Steven Lord il 25 Mar 2020
The [] as the second input is required when you want to specify a dimension, including 'all'. The function call max(A, 'all') only works if A and 'all' are compatibly sized.
>> max(1:3, 'all')
ans =
97 108 108
>> max(1:3, [], 'all')
ans =
3

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Dmaldo01
Dmaldo01 il 22 Apr 2016
Modificato: Dmaldo01 il 22 Apr 2016
This will work for all dimensions. If more efficient than ind2sub for less than 16000 elements.
[M,Index] = maxEl(MatVar)
index = size(MatVar);
Index = index*0;
M = max(MatVar(:));
A = find(MatVar==max(MatVar(:)),1);
for i = 1:length(index)
Index(i) = mod(ceil(A),index(i));
A = A/index(i);
end
Index(Index==0)=index(Index==0);

Yokesh
Yokesh il 16 Mag 2019
If matrix dimension is 'n', then max element can be found by:
max(max(.....maxn^2((A))...)
We have to include n^2 times max
  2 Commenti
Steven Lord
Steven Lord il 16 Mag 2019
No, you don't need to include multiple calls to max. See the accepted Answer for approaches that call max only once regardless of how many dimensions the input argument has.
Walter Roberson
Walter Roberson il 25 Mar 2020
Also it would only be n max calls.

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JPS
JPS il 6 Feb 2021
or you can use,
M = max(max(A));
  2 Commenti
Adrian Brown
Adrian Brown il 15 Mar 2021
hello,
There is any way for a matrix size NxM to get the k maximum element in the whole matrix not in rows or colomns but in only elements. for example matrix A = [1 3 2 5, 7 9 12 8, 12 8 9 0] for K= 3 the 3 maximum elements are 12 9 and 8 and I want to return there location in the matrix.
I really appreciate any help
Walter Roberson
Walter Roberson il 15 Mar 2021
A = [1 3 2 5; 7 9 12 8; 12 8 9 0]
A = 3×4
1 3 2 5 7 9 12 8 12 8 9 0
[best3, best3idx] = maxk(A(:),3)
best3 = 3×1
12 12 9
best3idx = 3×1
3 8 5
The three maximum values are 12, 12, and 9, not 12, 9, and 8. If you are interested in the three maximum unique values, then you need to explicitly take into account that some values occur more than once.
k = 3;
uA = unique(A, 'sorted');
nresults = min(length(uA), k);
results = cell(nresults, 1);
for K = 1 : k
this_max = uA(end-K+1);
results{K,1} = this_max;
results{K,2} = find(A==this_max).';
end
disp(results)
{[12]} {[ 3 8]} {[ 9]} {[ 5 9]} {[ 8]} {[6 11]}
The output is a cell array, in which the first column gives you the value that is the maximum, and the second column gives you all the linear indices into the array. The code could be modified to give row and column outputs instead without much change.
The code does not assume that the number of occurrences is the same for each of the values (if that were known to be true then a numeric array could be created instead of a cell array.)

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