if f(t)=1/t find the average rate of f with respect to t over the intervals from t=2 to t=3

syms t 
f(t)=1/t;
t=2;
t=3;
f(3)-f(2)/3-2
disp(t)

[Geoff Hayes]

karthik - what exactly is your question? Why do you have this line of code

f(3)-f(2)/3-2

? Is this supposed to be your average (though isn't being assigned to anything)? Be careful here...you may want to add some brackets around the numerator and denominator...

[KALYAN ACHARJYA]

Is this?

syms t 
f(t)=1/t;
t=2;
t=3;
ft_averg=(f(3)-f(2))/(3-2);
disp(ft_averg);

Answer 1

[Navya Seelam]

Hi,

Do you want to find average rate or average? Method to find both is given below

syms t 
f=@(t) 1./t;
tmin=2;
tmax=3;
average_rate=(f(3)-f(2))/(tmax-tmin)  % average rate of f(t) with respect to t
average=integral(f,tmin,tmax)/(tmax-tmin)  % average of f(t) 

[madhan ravi]

When t is defined as a function handle , why is there a need to define it as a symbolic variable?

[Navya Seelam]

Yes it isn't required.