How to identify and remove element if it is consecutively repeated a certain amount of times in an array

Hi,

I'd like to remove duplicates in an array only when it is consecutively repeated for a certain amount of time.

For example, say I have an array A=[1 2 3 3 3 3 5 6 2 8 7 3 3 2]; I'd like to identify and remove any element that is consequtively repeated for 3 times and more.

Specifically, I mean to identify and remove the 4 threes at A(3),A(4),A(5),A(6); While for the 2 threes at A(12), A(13), and the 3 twos at A(2),A(9),A(14), I'd like to keep them because either they are repeated but not consequtively, or not for 3 times and more.

I've searched how to remove duplicates, but it doesn't seem very helpful.

Is there any good solution to it?

[KALYAN ACHARJYA]

See the answer here (Multiple ways)

Answer 1

[Alex Mcaulley]

Following Jan's answer in this threat (link):

A = [1 2 3 3 3 3 5 6 2 8 7 3 3 2];
d = [true, diff(A) ~= 0, true]; 
n = diff(find(d));          
Y = repelem(n, n)
A = A(Y < 3)
A =

     1     2     5     6     2     8     7     3     3     2