running matrix in a loop to produce another matrix

Hi everyone, I have z

z = [1	1	0	0;
1	0	1	0;
1	0	0	1;
0	1	1	0;
0	1	0	1;
0	0	1	1;]

each of z's row are states that I want my code to go through one by one (from 1 1 0 0 to 0 0 1 1) , and after each state is run, it produces w. after running all the 6 states from z,

w = [a;
    a;
    a;
    a;
    a;
    a;];

Is there a code where I can run each state of z in a loop, and produces w?

[Ted Shultz]

what is "a"?

[JL]

"a" is calculated number. Meaning, for each time it loop, "a" is generated until the loop finishes.

Answer 1

[Ted Shultz]

This code will loop over each row of Z and put the results into w. I'm not sure what you want to do with each row.

z = [1  1   0   0;
1   0   1   0;
1   0   0   1;
0   1   1   0;
0   1   0   1;
0   0   1   1;]
 
numRows = size(z,1); % counts the number of rows
 
w = nan(numRows,1); % preallocate w;
 
for ii = 1:numRows
    thisRow = z(ii,:);
    
    % do something here to get a?
    a=sum(thisRow);
    
    w(ii) = a;
end

[JL]

Thanks for this! What if I change my z to

z = [1 2;
    1 3;
    1 4;
    2 4;
    1 6;];

and each time before it loop, first loop,

z = [
    1 3;
    1 4;
    2 4;
    1 6;]

and then for the second loop,

z = [1 2;
    
    1 4;
    2 4;
    1 6;];

and so on instead of the initial z

[Ted Shultz]

It looks like you are trying to do the same thing as this:

https://www.mathworks.com/matlabcentral/answers/477239-emptying-each-row-of-a-matrix-in-a-loop?s_tid=prof_contriblnk

[JL]

Yes, I put it up as anothe question