Memory overflown for the number to be saved

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Hi
I have string like this.
A={'IMSI=208016702935545 CI=20796 LAC=29188'};
I have done this
imsi=regexp(A,'\w*IMSI=\w*','match');
After doing that I get
imsi{1,1}= 'IMSI=208016702935545';
Again I do this to extract the numbe out of it
cellinfo=sscanf(char(imsi{1,1}),'%*5c%d');
But the length of IMSI is too long and is overflown. can anyone suggest something so that I can have cellinfo=208016702935545 ;
Thanks in advance
Avinash
  4 Commenti
Oleg Komarov
Oleg Komarov il 10 Set 2012
Do not double post.
Then what is CI? How do you get it?
Avinash bachu
Avinash bachu il 10 Set 2012
Sorry, my mistake.
I corrected the question now. Actually, there is no CI. CI was the name given in my code.

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Risposta accettata

Jan
Jan il 10 Set 2012
Modificato: Jan il 10 Set 2012
A = {'IMSI=208016702935545 CI=20796 LAC=29188'};
num = sscanf(A{1}, 'IMSI=%g', 1);
This should actually work, because the 15 digits of the number should be covered by the double precision. Alternatively import it as UINT64:
num = sscanf(A{1}, 'IMSI=%lu', 1);
Obviously the "%d" format saturates at the INT32 limits.
  1 Commento
Avinash bachu
Avinash bachu il 10 Set 2012
Thanks Jan.
Importing to uint64 didnt work. it was saturated at uint32 using %lu.
Thanks anyway

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Più risposte (1)

Oleg Komarov
Oleg Komarov il 10 Set 2012
Modificato: Oleg Komarov il 10 Set 2012
Using the look-behind operator in regular expressions without capturing the token:
cs = regexp(A,'(?<=IMSI=)\d+','match');
str2double(cs{:})
  5 Commenti
Avinash bachu
Avinash bachu il 10 Set 2012
Thanks Oleg. I tried cs = regexp(A,'(?<=IMSI=)\g+','match'); which didnt work. Do you have any other way around. i am very bad at matlab syntax.
Oleg Komarov
Oleg Komarov il 10 Set 2012
The '\d+' part in the regexp() does not relate to the sscanf() syntax.
cs = regexp(A,'(?<=IMSI=)\d+','match')
The line identifies characters belonging to the set '1234567890'.

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