How to sort matrix based on another matrix?

A=[3,2,1;8,3,1;6,4,2] and B=[5,9,2;9,2,1;8,7,4] Matrix A sort by row like A=[1,2,3;1,3,8;2,4,6] then based on A change values of B matrix like B=[2,9,5;1,9,2;4,7,8].

Answer 1

[Stephen23]

>> A = [3,2,1;8,3,1;6,4,2]
A =
  3  2  1
  8  3  1
  6  4  2
>> B = [5,9,2;9,2,1;8,7,4]
B =
  5  9  2
  9  2  1
  8  7  4
>> [A,X] = sort(A,2);
>> for k = 1:size(X,2), B(k,:) = B(k,X(k,:)); end
>> A
A =
  1  2  3
  1  3  8
  2  4  6
>> B
B =
  2  9  5
  1  2  9
  4  7  8

[K Venkatesh]

Thank you very much Stephen

Answer 2

[Rik]

Assuming you made a small typo in your B_out:

A=[3,2,1;8,3,1;6,4,2];
B=[5,9,2;9,2,1;8,7,4];

for row=1:size(A,1)
    [A(row,:),order]=sort(A(row,:));
    B(row,:)=B(row,order);
end
clc,disp(B)

[K Venkatesh]

Thank you very much Rik