Create new table wit differentiate or diff from existing timetable

I've got below timetable with daily measurements from my gas meter at home:
Timestamps GasM3
____________________ _____________
14-Aug-2019 00:00:00 331.15
25-Aug-2019 00:00:00 332.37
26-Aug-2019 00:00:00 332.74
27-Aug-2019 00:00:00 333.97
I would like to know the daily consumption, so I tried playing with "differentiate" & "diff" to get these values in a new table.
I've tried
Test1 = differentiate(DailyGasDataTimeTable)
which gave the following error:
Error using Visualization: Differential test</a> (line 17</a>)
'differentiate' requires Curve Fitting Toolbox
and
Test2 = diff(DailyGasDataTimeTable)
which gave the following error:
Undefined function 'diff' for input arguments of type 'table'.
Error in Visualization: Differential test (line 17)
Unfortunately I'm stuck, please advise.
Kind regards,
Daniel

Risposte (4)

Vinod
Vinod il 28 Ago 2019
Modificato: Vinod il 28 Ago 2019
You can extract the specific column, GasM3, from the timetable and use the diff function. Something like this:
data = thingSpeakRead(YourChannelNum,'OutputFormat','TimeTable');
deltaM3 = diff(data.GasM3);
newTable = timetable(data.Timestamps(2:end), deltaM3)

2 Commenti

Dear Vinod,
Great, it works!
Thank you very much
Regards Daniel
Note that it might make more sense to use gradient than diff

Accedi per commentare.

What if my timetable is missing entries, or the entries are unevenly timed?
Hello, Thanks for your answer it's very helpful!
What if I the variable I what to differentiate is not a fixed name and will be changing along the code? for example:
for i=1:10;
deltaM(i) = diff(data.GasM3{i}); % -->> does not work with this notation
end

3 Commenti

N = 10;
deltaM = cell(N,1);
for i = 1 : N
varname = "GasM3" + i;
deltaM{i} = diff(data.(varname));
end
This assumes you are looking for GasM31 GasM32 GasM33 and so on up to GasM310
Or you could use a numeric index.
T = array2table(magic(4))
T = 4×4 table
Var1 Var2 Var3 Var4 ____ ____ ____ ____ 16 2 3 13 5 11 10 8 9 7 6 12 4 14 15 1
A = T{:, 3} % Equivalent to T.Var3
A = 4×1
3 10 6 15
If you're release R2023a or later, you may be able to compute directly on the table or timetable, as described on this documentation page.
T2 = diff(T)
T2 = 3×4 table
Var1 Var2 Var3 Var4 ____ ____ ____ ____ -11 9 7 -5 4 -4 -4 4 -5 7 9 -11
Thanks Walter and Steven, very useful information.
Just to add some extra information, I found the function wildcardPattern very useful to get similar names from table. would be something like:
varname = "GasM3" + wildcardPattern;

Accedi per commentare.

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R2019a

Richiesto:

il 28 Ago 2019

Commentato:

il 22 Ago 2023

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