How can I establish that my function must have a fixed value after a specific condition occurs?

Hi all,

i'm looking for a method to establish a value for my function "S" . For example if T(1,i)==2 i want my function is S(i)=0, but also S(1+n)=0 with n=i:length (t). I'm simulating when a failure occurs and "S" is the function of the performance of my system: if a failure occurs the performance of my system must be zero from the time "i" when it occurs till the end of the time interval. I have the same situation when a failure occurs but the performances of my system go to "0.5": in this case if T(1,i)==1, S(i)=0.5 and also S(1+n)=0.5 with n=i:length (t).

How can i write these conditions?

I report here my code

T = [3 3 3 1 2 3 3 1 2 3] 

t=1:10;  % time interval 
  for i=1:length (t)
      if T(1,i)==1
       S(i)=0.5;
%        S(1+n)=0; n=i:length(i) % i want that all my values S(i+1), S(i+2)...S(i+n)=0.5 
                                 % from i such that T(1,i)==2 to length (t) 
    elseif T(1,i)==2
       S(i)=0;
%        S(1+n)=0; n=i:length(i)  % i want that all my values S(i+1), S(i+2)...S(i+n)=0 
                                   % from i such that T(1,i)==2 to length (t) 
    else 
        S(i)=1;
   end
  end
 

Thanks for who will answer me

[AlexDp]

I try to explain better. In the case of T = [3 3 3 1 2 3 3 1 2 3] i expect to obtain a

plot (t,S) like that in figure. The behavior of the function "S" will be: "1" for every "3", but T(1,4)=1 so the function will assume 0.5 for all the values till the end of t. How can i write this function? I hope i was more clear now. Thanks for your answers.

Answer 1

[Bruno Luong]

Assuming your T contains 1,2,3.

V = [0.5, 0, 1]; % values correspond to 1,2,3
S = V(T)

[madhan ravi]

Ah , bullseye!