How to visualise data value with x-y coordinate in an image

3 visualizzazioni (ultimi 30 giorni)
Hello, suppose I have x-y coordinate and z value as the grades of the points. How can I visualize my data in 2-D colormap ? (I want to show x-y cordinate and different colors for different values at every points inside the image). I am attachng sample data text file and regarding image.
Please help.
  2 Commenti
Walter Roberson
Walter Roberson il 15 Set 2019
I suspect you want griddedInterpolant()
Along with a colormap such as 'hot' or perhaps 'autumn'
RAJ DATTA
RAJ DATTA il 16 Set 2019
yes. I found I need to interpolate to and a matrix should be created for [x,y, data]. only then I can make an image. Thank you sir for your idea.

Accedi per commentare.

Risposte (1)

Image Analyst
Image Analyst il 15 Set 2019
Try something like
data = dlmread(filename, ' ');
x = data(:, 1);
y = data(:, 2);
grayLevel = data(:, 3);
grayImage = zeros(ceil(max(y)), ceil(max(x)));
for k = 1 : length(x)
row = round(y(k));
col = round(x(k));
grayImage(row, col) = grayLevel(k);
end
grayImage = mat2gray(grayImage);
imshow(grayImage, 'ColorMap', jet(256));
colorbar;
  4 Commenti
Image Analyst
Image Analyst il 15 Set 2019
Not only the blue, but for most of them. There are 181 pixels that are not zero. But most of your image locations do not have a gray level defined for them, so they are left as zero and appear as blue.
data = dlmread('md1.txt', ' ');
x = data(:, 1);
y = data(:, 2);
grayLevel = data(:, 3);
grayImage = zeros(ceil(max(y)), ceil(max(x)));
for k = 1 : length(x)
row = max([1, round(y(k))]);
col = max([1, round(x(k))]);
grayImage(row, col) = grayLevel(k);
fprintf('Assigning %d to row %d, column %d.\n', grayLevel(k), row, col);
end
minGL = min(grayImage(:))
maxGL = max(grayImage(:))
grayImage = mat2gray(grayImage);
imshow(grayImage, [], 'ColorMap', jet(256));
colorbar;

Accedi per commentare.

Prodotti


Release

R2018a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by