How to use interp1 to stretch out smaller vector to the size of larger vector?

So I have two vectors, lets call them A and B. A is the smaller vector, and has 1260 columns. B is the larger vector and has 1778 columns. I want to take an average of both these vectors. This is being hard because they are different sizes. Is there a way for me to use interp1 so that I can stretch out the smaller vector to match the size of the larger vector? Any help would be really appreciated!

Answer 1

[John D'Errico]

Assuming that you intend to create a vector of averages, do this:

Ahat = interp1(1:1260,A,linspace(1,1260,1778));

C = (Ahat + B)/2;

[Zuha Yousuf]

Thank you so much! You have no idea how much this has helped me!

[SURESH KUMAR]

it helped me alot . I wanted to strech the time series data without changing the y axis values and it does perfectly however i had to come up with understading about the duration for which i wanted my expension.. Anyways Thanks

Here is my if anyone needs

powNew=interp1(1:legnth(A),A,linspace(1,legnth(A),legnth(A)+increasementYourValue))