Azzera filtri
Azzera filtri

How to segregate folders level wise and list the files folderwise

7 visualizzazioni (ultimi 30 giorni)
In Matlab 2016 onwards, commands like dir(**/*.extension) is available. However, it lists all the file list with its Path. The task afterward is critical. 1. Obtain Subfolders 2. Obtain Files and Subsubfolders with their level. 3. Extract the directory name and file name in cell array.
Are there modified ways or shortcut commands to obtain this info.

Risposta accettata

Image Analyst
Image Analyst il 5 Ott 2019
There is a .isdir property on the returned files that you can check. In addition there is a function called isfolder() that you can also use. Try this:
files = dir('**/*.*')
areFolders = [files.isdir]
folders = files(areFolders)
dotOrDotDot = strcmp('.', {folders.name}) | strcmp('..', {folders.name})
folders = folders(~dotOrDotDot)
folderNames = {folders.name}

Più risposte (0)

Categorie

Scopri di più su File Operations in Help Center e File Exchange

Prodotti

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by