Need help with simple loop

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Joost de Witte
Joost de Witte il 9 Ott 2019
Risposto: Walter Roberson il 9 Ott 2019
I've got a matrix of 35040x14 (35040x 15minutes). I now want to to get the maximum value per hour over these 14 colomns. I've made the following for the first hour:
myData = 35040x14
oneHour = myData(1:4,:);
maxValuePerHour = max(oneHour);
oneHour gives me a 4x14 matrix which I then took the maximum per column from resulting in a maxValuePerHour matrix of 1x14, as intended. However, I want to loop this process so I end up with a 8760x14 (35040/4) where in the 8760 rows represent maximum values per hour for the entire data set.
Any help would be appreciated. Thank you.

Risposte (1)

Walter Roberson
Walter Roberson il 9 Ott 2019
squeeze( min( reshape(myData, 4, [], size(myData,2)), 1) )

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