What syntax can I use, say, in the calculation of the number of tanks of a plant where the length of each tank should not be greater than 50? Below is the code I tried...

while length > 50

lbratio= input('\nEnter length/breadth ratio: ');
vol = ret_time/24 * q;
area = q/ofr;

breadth = sqrt(area/lbratio);
length = lbratio*breadth;
depth = vol/area;

fprintf(1,'Data :\n');
fprintf(1,'Volume is %10.5f\n', vol);
fprintf(1,'Area is %10.5f\n', area);
fprintf(1,'length is %10.5f\n', length);
fprintf(1,'breadth is %10.5f\n', breadth);
fprintf(1,'depth is %10.5f\n', depth);
fprintf(1,'length/breadth ratio is %10.5f', lbratio);

end

Answer 1

[Wayne King]

length is a MATLAB function so you should try to avoid using variable names that are the same as MATLAB function names. area is also a MATLAB function. Further, your post says the length should not be greater than 50, but your while loop condition is while length > 50

In your example you give us no idea what a reasonable starting value for the values of a number of variables so I'm not sure how you expected anyone to help you. Here I have just assigned arbitrary values to get it the loop to work.

I've also changed the while condition to be length less than or equal to 50 -- I've renamed length to len and I've renamed area to ar.

 len = 0;
 ret_time = 0;
 q = 1;
 ofr = 1;
 while len <= 50

 lbratio= input('\nEnter length/breadth ratio: ');
 vol = ret_time/24 * q;
 ar = q/ofr;

 breadth = sqrt(ar/lbratio);
 len = lbratio*breadth;
 depth = vol/ar;

 fprintf(1,'Data :\n');
 fprintf(1,'Volume is %10.5f\n', vol);
 fprintf(1,'Area is %10.5f\n', ar);
 fprintf(1,'length is %10.5f\n', len);
 fprintf(1,'breadth is %10.5f\n', breadth);
 fprintf(1,'depth is %10.5f\n', depth);
 fprintf(1,'length/breadth ratio is %10.5f\n', lbratio);

 end