Remove strings from an array based on string length
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Aravind Vicinthangal Prathivaathi
il 13 Ott 2019
Modificato: Stephen23
il 14 Ott 2019
Hello. I'm trying to remove strings from a string array based on string length. I want to remove strings with lesser than 2 alphabets. I tried the following code but I'm getting an error
clc; clear;
s = {'a';'b';'cat';'apple'};
s1 = string(s);
String_length = strlength(s1);
Min_length = 2;
Modified_string = [s1 String_length];
indices = find(Modified_string(:,2) < Min_length);
Modified_string(indices,:) = [];
Error using <
Comparison between string and double is not supported.
Error in Dummy (line 8)
indices = find(Modified_string(:,2) < Min_length);
1 Commento
Stephen23
il 14 Ott 2019
Modificato: Stephen23
il 14 Ott 2019
This approach is very complex, with one implicit conversion from numeric to string, which then requires an explicit conversion from string to numeric. Pointless type conversions should be avoided, as they just slow code down without any benefit.
Here is a much simpler and more efficient solution using basic MATLAB indexing:
out = s1(strlength(s1)>=2))
Risposta accettata
Thiago Henrique Gomes Lobato
il 13 Ott 2019
For you to do the comparison you must first convert the string to a numeric. The following code should solve your problem:
clc; clear;
s = {'a';'b';'cat';'apple'};
s1 = string(s);
String_length = strlength(s1);
Min_length = 2;
Modified_string = [s1 String_length];
indices = find( str2double(Modified_string(:,2)) < Min_length);
Modified_string(indices,:) = []
Modified_string =
2×2 string array
"cat" "3"
"apple" "5"
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