Varargout - How to realize function call

Hey guys,

let us assume the following function:

function [out1,out2,out3]=test(j,k)
out1= nargin;
out2 = j-k;

if out2 == 10
    out3 = 5;
end

end

The function call [val1,val2,val3] = test(10,11) returns an error because c is obviously undefined. How do I make this code run so that out3 is returned when it exists?

Thanks for your help!

[Guillaume]

The function call [val1,val2,val3] = test(10,11)

will always require 3 outputs from the function, so test must always return at least 3 outputs for that call to be valid.

That's independent of whether or not the function only returns some outputs under some conditions.

Answer 1

[Stephen23]

Simpler:

function [out1,out2,out3]=test(j,k)
out1= nargin;
out2 = j-k;
out3 = [];
...
if out2 == 10
    out3 = 5;
end
end

Answer 2

[per isakson]

varargout exercise. Try something like this

function varargout = test( j, k )
    out1= nargin;
    out2 = j-k;
    if out2 == 10
        out3 = 5;
    end
    if exist( 'out3', 'var' ) == 1
        varargout = { out1, out2, out3 };
    else
        varargout = { out1, out2, [] };
    end
end

or

function varargout = test( j, k )
    out1= nargin;
    out2 = j-k;
    if out2 == 10
        out3 = 5;
    else
        out3 = [];
    end
    varargout = { out1, out2, out3 };
end

Answer 3

[Dario Walter]

Thanks yor your help folks! I thought that a more sophisticated way exists than setting out = [ ]. Anyway, I am happy with that :)