Line, column, and value in matrix B of repeated values ​​in A.

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Hi. Good day.
I have a code that indicates line, column and value in matrix B, which are in vector A.
But this code does not allow me to have repeated values ​​in matrix B, which is already in vector A
% ________________________________
clc; clear; close all; format short;
A = [10 8 8 6 2];
 B = [10 12 16 15 11
       8 16 21 6 26
       85 61 21 48 11
       41 52 62 44 2
       29 51 55 59 16
       98 95 93 92 99];
  
for b = 1: 1: 5
     Value (b) = A (1, b);
     [row (b), col (b)] = find (B == Value (b));
end
Value
row
col
=========================================
Command Window
Value =
    10 8 8 6 2
row =
     1 2 2 2 4
col =
     1 1 1 4 5
===========================================
What do I have to do to make the code detect the position of repeated values ​​in matrix B
Something like that:
A = [10 8 8 6 2];
 
B = [10 12 16 15 11
     8 16 21 6 26
     8 61 21 48 11
     41 52 62 44 2
     29 51 55 59 16
     98 95 93 92 99];
Command Window
Value =
    10 8 8 6 2
row =
     1 2 3 2 4
col =
     1 1 1 4 5
----------------------------
Hoping you can help me.
Thank you.
  2 Commenti
per isakson
per isakson il 7 Nov 2019
Is it true that
  • a value that is repeated in A must be repeated the same number of times in B ?
  • repeated values in A are consecutive
Ricardo Gutierrez
Ricardo Gutierrez il 8 Nov 2019
A value that is repeated in A must be repeated the same number of times in B? ==== Yes
Repeated values in A are consecutive ===== Yes
In fact the vector A by a mathematical process was formed by data of the matrix B therefore the values in A must be in B.

Accedi per commentare.

Risposta accettata

JESUS DAVID ARIZA ROYETH
JESUS DAVID ARIZA ROYETH il 8 Nov 2019
solution :
[row,col]=find(ismember(B,A))

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