Azzera filtri
Azzera filtri

How idx runs and give its value ?

16 visualizzazioni (ultimi 30 giorni)
Atique Barudgar
Atique Barudgar il 8 Nov 2019
Risposto: M il 8 Nov 2019
a=[34.8 31 29 26.7 39.5]; %dummy data
n=33;
[val,idx]=min(abs(a-n));
minVal=a(idx)
After running:
Now I am not clear when in answer idx=1
then how a(idx)=34.8 came
Even I am not clear about idx...why its values change everytime

Risposte (1)

M
M il 8 Nov 2019
abs(a-n) =
1.8000 2.0000 4.0000 6.3000 6.5000
then min(abs(a-n)) = 1.8, and the location of this minimum value (idx) appears at the first value of the vector.
Where is the problem ?

Categorie

Scopri di più su Startup and Shutdown in Help Center e File Exchange

Tag

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by