Sorting matrices

so I have two matrices:

A = [4 6 3 2 9 0 1 5 7 8]

B = [6 5 2 4 0 8 3 7 4 9]

I want to sort matrix A in ascending order, but I want B to correspond with the sorting so that the column match. so if I sort(A), I want B to look like this:

A = [0 1 2 3 4 5 6 7 8 9]

B = [8 3 4 2 6 7 5 4 9 0]

Matrix B can have more than one rows. B is not to be sorted, it just follow the sorting of matrix A. A and B can be in one matrix so as long as I can sort the first row, all the following rows will follow. I would like some ideas about doing this. Thanks.

Answer 1

[Matt Fig]

[As,I] = sort(A);
Bs = B(I);

To sort along the rows, use the dim argument to SORT.

[Jason]

This only work if B have one row. I just tried with B having two rows and it combines B into one row. Is there another way to do this if B has more than one rows? like:

B = [6 5 2 4 0 8 3 7 4 9; 6 5 2 4 0 8 3 7 4 9]

[Sean de Wolski]

Bs = B(:,I);

[Matt Fig]

Sean de has the correct solution to this further problem. When working with matrices and sorting along dim2, I contains the column indices of the sort for each row.

Thus you must use them that way when indexing into B.

[Jason]

Got it now. Thanks.

[Mohamed Helmy]

Thanksssssssss

Answer 2

[Tim Zaman]

Append A to B so that

i believe the code is C=[A;B] so that:

C = [4 6 3 2 9 0 1 5 7 8;

     6 5 2 4 0 8 3 7 4 9]

Then you say "sort(C,1)" so that the sorting is done for the first column

Have fun

PS makeup and layout in this textbox is awful

[Sean de Wolski]

What about it is awful?