Not enough input arguments?

1 visualizzazione (ultimi 30 giorni)
Victor Popa-Simil
Victor Popa-Simil il 14 Dic 2019
I'm trying to make a user-define function that accepts time as an input and gives me an output of height. Here is the code I am using currently.
For some reason it keeps giving me the error on line 2 that I do not have enough input arguments. What does this mean? Thank you!
function h=height(t)
h=(-(9.8/2).*t.^2)+(125.*t)+500;
end

Risposta accettata

Image Analyst
Image Analyst il 14 Dic 2019
How are you calling it? What value are you passing in for t? You're not just clicking the green run triangle without giving it a value for t are you? So, let's say t was 10. Are you doing
t = 10;
h = height(t); % Pass in t to the height() function.
fprintf('For t = %.1f, height = %f.\n', t, h);
So, what is your program for calling your height() function? Evidently from the error it thinks you're doing this:
h = height(); % Not passing in anything for t. This will throw an error.
or else you're clicking the green run triangle which will try to run the function without sending in anything for t.
  1 Commento
Victor Popa-Simil
Victor Popa-Simil il 14 Dic 2019
I completely skipped over the fact that I had no value for t and that made the error. Simple mistake. Thank you!

Accedi per commentare.

Più risposte (0)

Categorie

Scopri di più su MATLAB Mobile Fundamentals in Help Center e File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by