Finding Unique values for First Row of a Matrix

I have a matrix which I intend to use, such that, I have to keep the uniqe elements of the first row in a specific manner, Following is to describe the process in a bit detail:

We scan the first row and keep it as such if all the elements are unique. Otherwise for a repeating value we select the next value which is uique. For example for the following matrix A:

The output should be Output = [5 6 7 9 11], where first element A(1,1) is kept as such, since the the next element in the first row i.e. A(1,2) = A(1,1), we choose next unique element in this column i.e. A(2,2) , And So on to scan the entire first row without repetition. This way to achieve the desired output for generalized matrix ... Any input will be appreciated .

[Walter Roberson]

What should happen if you reach a column in which all of the entries are already in the list?

[MShia]

Please assume that its not the case, we will always find unique entries(may be I couldnt reflect that in the example matrix)

[Walter Roberson]

ismember() the current column against the list of values already used. The first item not present is the one to output and add to the list of values used.

[MShia]

Thanks alot ..

Answer 1

[Andrei Bobrov]

Let A - your array.

output = A(1,:);
for i = 2:numel(output)
    u = unique([output(1:i-1)';A(:,i)]);
    output(i) = u(i);
end

[MShia]

Thanks Sir very elegant solution! The only modification I had to do, was to use the unique command with "stable" option to maintain the sequence. I really appreciate it .