
why matlab gave me 5 eigenvectors for 6*6 matrix?
6 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
reza hamzeh
il 27 Dic 2019
Commentato: Christine Tobler
il 6 Gen 2020
hi. i wanted to get eigenvectors of a 6*6 matrix. matlab must gave me 6 eigenvectors and 6 eigenvalues but it gave me 6 eigenvalues and 5 eigenvectors...
how is it possible?
clear;
syms x;
Ha='[x/2 0 0 0 0 0;0 -x/2 x 0 0 0;0 x -x/2 0 0 0;0 0 0 x/2 0 0;0 x 0 x 0 0;x 0 x 0 x 0]';
Haf = str2func(sprintf('@(%s)%s;','x',Ha));
[vectors,values]=eig(Haf(x));
vectors
0 Commenti
Risposta accettata
KALYAN ACHARJYA
il 27 Dic 2019
Modificato: KALYAN ACHARJYA
il 27 Dic 2019
An nxn matrix M can have up to n unique eigenvalues and eigenvectors. If its characteristic equation det(M-lamda*I)=0 has repeated roots, then you get fewer than n eigenvectors

I have copied from here
1 Commento
Christine Tobler
il 6 Gen 2020
Note that this is true for the eig function used on symbolic variables. For numeric variables, you can rely on getting exactly n eigenvalues and eigenvectors from an n-by-n matrix.
This is because numeric algorithms are backward stable: For an input matrix A, they return eigenvalues and eigenvectors of a matrix B which is close to the matrix A (by about machine round-off error). There is always such a matrix B which has n eigenvalues and eigenvectors, and this is always chosen by the algorithms used in eig.
Più risposte (0)
Vedere anche
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!