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can't get all the other characters = 26
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Write a function m-file called stringcode that takes a string as input and produces an array containing a code for each letter in the string with A = 0, B = 1, ..., Z = 25 and all other characters getting the value 26.
function num = stringcode( word )
asc= double((word))
if asc >= 33 & asc <=47
asc = 26
else asc= double(upper(word))
end
asc= double(upper(word))
num = asc - double('A'); % simple arithmetic
end
2 Commenti
James Tursa
il 26 Gen 2020
asc is a vector, but your code treats it as a scalar. You either need to wrap your code in a loop to do each character one at a time, or you need to vectorize your code.
Risposte (1)
Image Analyst
il 26 Gen 2020
You don't need all that complicated stuff. You almost had it at the end, so simply subtract 'A' and you're done. None of that foregoing stuff is needed. Watch:
>> num = 'ABCDEFGHIJKLMNOP' - 'A'
num =
0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
2 Commenti
Image Analyst
il 26 Gen 2020
In your function of course:
function num = stringcode( word )
num = word - 'A'
num(num<0 | num>25) = 26;
Just throw out all that useless stuff you had and have just those three lines. Basically the same as what you have except you don't need to cast to double
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