How to decrease the time to obtain all possible numerical combinations using the for loop in MATLAB?
5 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
Luiz Augusto Brusaca
il 2 Feb 2020
Modificato: Luiz Augusto Brusaca
il 2 Feb 2020
Hi all,
I need to decrease the time of possible numerical combinations using for loop. In short, I am analyzing electromyography (EMG) data and doing some simulations with times among some tasks developed by office workers to see which combination creates the greatest variation in muscle. The simulations for 3 and 4 tasks didn't take me long, the problem started when I tried to get combinations for 5 tasks, I left the loop running for more than 2 hours and I still couldn't finish the combinations.
Here is my code:
% Time simulation for six tasks
% Proportion of time
% CWsit | CWstand | NCWsit | NCWstand | NonDeskW | WBreak
% CW = computer work
% NCW = Non-computer work
const = 30; % Here, I set the value 30, because my first task cannot have a value less than that
work_temp = [];
for i = 0:(90-const)
for j = 0:(90-const-i)
for k = 0:(90-const-i-j)
for l = 0:(90-const-i-j-k)
m = 90-const-i-j-k-l;
work_temp = [work_temp;[const+i j k l m]];
end
end
end
end
% note: WBreak has a fixed time of 10% (0.1 in proportion)
% Adding the Wbreak task time vector
work_temp = [work_temp, 10 + zeros(length(work_temp),1)];
Is there any way to make the loop faster?
I know that this loop will result in a huge amount of combinations, so I don't know if it helps much, but the first task cannot have more than 70% of time. (min 30 and max 70). Perhaps the loop can be stopped when get that value.
EDITED: With the help of Walter Roberson (see below) , I was able to obtain the output size, with that value I was able to make the pre-allocation.
% Finding out what matrix size do I need to store my output
const = 30;
[I, J, K, L] = ndgrid(0:90-const);
mask = J <= I & K <= J & L <= K ;
M = 90 - const - I(mask) - J(mask) - K(mask) - L(mask );
% For nested loop to simulate all possible times
const = 30;
work_temp = zeros(length(M),5); % Preallocation (save a lot of time)
c = 0;
tic
for i = 0:(90-const)
for j = 0:(90-const-i)
for k = 0:(90-const-i-j)
for l = 0:(90-const-i-j-k)
m = 90-const-i-j-k-l;
c = c + 1;
work_temp(c,:) = [const+i j k l m];
end
end
end
end
toc
Elapsed time is 0.355317 seconds.
Thanks in advance,
Luiz Augusto
3 Commenti
Risposta accettata
Walter Roberson
il 2 Feb 2020
[I, J, K, L] = ndgrid(0:90-const);
mask = J <= I & K <= J & L <= K;
M = 90 - const - I(mask) - J(mask) - k(mask) - L(mask);
3 Commenti
Walter Roberson
il 2 Feb 2020
[I, J, K, L] = ndgrid(0:90-const);
mask = J <= I & K <= J & L <= K;
M = 90 - const - I(mask) - J(mask) - K(mask) - L(mask);
>> size(M)
ans =
635376 1
Più risposte (0)
Vedere anche
Categorie
Scopri di più su Loops and Conditional Statements in Help Center e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!