Vector averaging with mean command

Hello! I don’t quite understand how to use this command, I need to average a 1x533 vector

Averaging1=mean(X,10);
Averaging2=mean(X,50);
Averaging3=mean(X,100);

I need to average over 10, 50 and 100, when I use such commands nothing happens

[KSSV]

what do you mean by averaging over 10, 50 and 100?

[Lev Mihailov]

average vector by blocks of 10 and 50

X=[1:100]
Averaging1=mean(X,10);
Averaging1=[5.5  15.5 ....]

Answer 1

[Rik]

A faster method than a for-loop is using movmean and throwing out the results you don't need. This will also take care of the case where you have an incomplete trailing block.

clc
X=rand(28,1);
n=10;

tic
Averaging1=[mean(X(1:10)); mean(X(11:20)); mean(X(21:28))];
toc

tic
Averaging2=movmean(X,[0 n-1]);
Averaging2=Averaging2(1:n:end);
toc

isequal(Averaging1,Averaging2)

[Lev Mihailov]

And if 'n' is a vector (at different intervals), what should I do?

[Rik]

Do you mean this should be repeated for different values of n? Or do you have a vector with all group sizes?

%example for the latter:
n=[2 4 3];
Averaging1=[mean(X(1:2));mean(X(3:6));mean(X(7:9))]

[Lev Mihailov]

I got a vector of values ​​(necessary areas) that need to be averaged

Answer 2

[Bhaskar R]

Second argument of mean is dimension, your input vector X is 1x533 vector 1D vector.

1) I assume you need mean of the values from 1 to 10, 1 to 50 and 1 to 100 values

Averaging1=mean(X(1:10));
Averaging2=mean(X(1:50));
Averaging3=mean(X(1:100));

or 2) I assume you need mean of the values from 1 to 10, 11 to 50 and 51 to 100 values then

Averaging1=mean(X(1:10));
Averaging2=mean(X(11:50));
Averaging3=mean(X(51:100));

[Lev Mihailov]

X=[1:1:553];
Averaging1=mean(X(1:10));

such a solution is good, but can you use a loop to make a vector along the entire length of the vector?

Averaging1=mean(X(1:10)); Averaging1=mean(X(11:21));  Averaging1=mean(X(22:32));

[Rik]

You are ignoring the fact that your padding influences the mean value of the final block. You should probably use something like the code below.

if mod(numel(X),n)~=0
    elem_count=numel(X);
    X( (end+1):(n*ceil(numel(X)/n)) )=0;
    X=reshape(X,n,[]);
    divs=n*ones(1,size(X,2)-1);
    divs(end+1)=mod(elem_count,n);
    Averaging3=sum(X,1)./divs;
    Averaging3=Averaging3';
else
    X=reshape(X,n,[]);
    Averaging3=mean(X,1);
    Averaging3=Averaging3';
end