using the data from struct

4 visualizzazioni (ultimi 30 giorni)
Mohamed Ibrahim
Mohamed Ibrahim il 14 Feb 2020
Commentato: Fangjun Jiang il 14 Feb 2020
hello i have a small problem
i have a code and when i run it its solution appear as a struct
the problem is i want to take some data from this struct aىd use it as a input for another code but i can't when i enter the name of a field in structure for example CL matlab tells me Undefined function or variable 'CL'.
i want this structure outputs to appear in my workspace like that
any suggestions please :)
  2 Commenti
Fangjun Jiang
Fangjun Jiang il 14 Feb 2020
out of breath reading your question. add proper punctuation marks.
Stephen23
Stephen23 il 14 Feb 2020
Modificato: Stephen23 il 14 Feb 2020
You should allocate the structure to a variable, e..g.:
S = function_that_returns_a_structure(...);
Then you can trivially refer to its fields, e.g.:
S.Re
S.CD
S.Ncrit
etc.
"i want this structure outputs to appear in my workspace like that"
Do not convert structure fields to variables, unless you want to force yourself into writing slow, complex, buggy code that is hard to debug.

Accedi per commentare.

Risposta accettata

Fangjun Jiang
Fangjun Jiang il 14 Feb 2020
If you can't change the other program, Out=YourOtherProgram(), where "Out" is a data like "ans" in your picture,
then you can use Out.CL, Out.CD, etc.
There are functions like struct2array(), struct2cell() that you can use.
  2 Commenti
Mohamed Ibrahim
Mohamed Ibrahim il 14 Feb 2020
thanks for your replay :)
i write this line at the end of my code
cth=ans.CL;
and matlab gives me this error message
Attempt to reference field of non-structure array.
Error in xfoil (line 239)
cth=ans.CL;
Fangjun Jiang
Fangjun Jiang il 14 Feb 2020
"ans" is the reserved variable name used by MATLAB. Use a different name.

Accedi per commentare.

Più risposte (0)

Categorie

Scopri di più su Structures in Help Center e File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by