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Can I get information of used method arguments validation by meta.class

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Hello,
I would like to collect information about used validation in arguments block of class methods.
Currently I get information about property validation through meta.class,
mco = ?memmapfile;
findobj(mco, 'Name','Filename' )
ans =
property with properties:
Name: 'Filename'
Description: ''
DetailedDescription: ''
GetAccess: 'public'
SetAccess: 'public'
Dependent: 1
Constant: 0
Abstract: 0
Transient: 0
Hidden: 0
GetObservable: 0
SetObservable: 0
AbortSet: 0
NonCopyable: 1
GetMethod: @C:\Program Files\MATLAB\R2019b\toolbox\matlab\iofun\@memmapfile\memmapfile.m>memmapfile.get.Filename
SetMethod: @C:\Program Files\MATLAB\R2019b\toolbox\matlab\iofun\@memmapfile\memmapfile.m>memmapfile.set.Filename
HasDefault: 0
Validation: [0x0 meta.Validation]
DefiningClass: [1x1 meta.class]
Here I take the meta.Validation. For example in my custom class:
>> findobj(?MyRectangle, 'Name','length' ).Validation
ans =
Validation with properties:
Class: [1x1 meta.class]
Size: [1x0 meta.ArrayDimension]
ValidatorFunctions: {@mustBeNumeric}
Can I get this information for argument validation in class methods as well? By meta.class ? Does anybody know how to do it?
  3 Commenti
TADA
TADA il 27 Dic 2021
to make things worse, when I add the arguments block, metaclass no longer identifies the argumets list at all:
classdef Class
methods
function z = foo(obj, x, y)
z = x*y;
end
end
end
mc = ?Class;
mf = mc.MethodList(strcmp({mc.MethodList.Name}, 'foo'));
mf.InputNames
ans =
3×1 cell array
{'obj'}
{'x' }
{'y' }
When I add the arguments validatin block:
classdef Class
methods
function z = foo(obj, x, y)
arguments
obj
x {mustBeNumeric(x)}
y {mustBeNumeric(y)}
end
z = x*y;
end
end
end
mc = ?Class;
mf = mc.MethodList(strcmp({mc.MethodList.Name}, 'foo'));
mf.InputNames
ans =
1×1 cell array
{'varargin'}
Thomas Ewald
Thomas Ewald il 12 Dic 2023
Hello!
I am currently dealing with the same problem. Adding an argument validation results in the InputNames property returning only 'varargin'. Has some solution been found yet?
All the best! TE

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