How to find the position of a real vector in a matrix?

4 visualizzazioni (ultimi 30 giorni)
I do have a very big matrix of real numbers, I need a function that takes a vector as input and returns its position in the matrix.
An example:
A =[
0.7081 0.0797 0.1418 0.5849 0.1305
0.0738 0.4849 0.5060 0.8479 0.5003
0.8723 0.1511 0.6346 0.0683 0.7673
0.2021 0.4461 0.7313 0.7355 0.4157
0.7050 0.8435 0.8158 0.2139 0.8008]
Suppose I want to find the position of
v=[ 0.7081 0.0797 0.1418 0.5849 0.1305]
in A
How can I do it?
I edited the question
  2 Commenti
Walter Roberson
Walter Roberson il 6 Mar 2020
You cannot. Those values do not exist in the matrix.
You need to give the command
format long g
And then display A again.

Accedi per commentare.

Risposte (2)

dpb
dpb il 6 Mar 2020
>> find(ismember(A,v,'rows'))
ans =
1
>>
works here, but in general for floating point values
>> find(ismembertol(A,v,2*eps,'byrows',1))
ans =
1
>>
is more robust and will avoid surprises.
  2 Commenti
Cantor Set
Cantor Set il 6 Mar 2020
I tried it on a very big matrix of real numbers it returned
ans =
Empty matrix: 0-by-1
dpb
dpb il 7 Mar 2020
>> find(ismembertol(w,c,2*eps,'byrows',1))
ans =
1
>>

Accedi per commentare.


Walter Roberson
Walter Roberson il 6 Mar 2020
Dists = pdist2(A, v);
[mindist, rowidx] = min(Dists) ;
if mindist > some_tolerance
error('row not found') ;
end
  3 Commenti
dpb
dpb il 7 Mar 2020
Modificato: dpb il 7 Mar 2020
Shouldn't w/ the given example data...altho suppose it's possible with the real data instead of that rounded off in the pasted text instead of actual data from memory.
>> D=pdist2(w,c);
>> [minD,ixMin]=min(D)
minD =
0
ixMin =
1
>>
With the rounded data from the posting it's identically zero.
Did you look at what was returned at all or just complain...

Accedi per commentare.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by