Conversion from uint8 to ascii to number
Mostra commenti meno recenti
I am currently working with RS232 serial communication between a Trimble gps and a Speedgoat real time computer in Simulink. From the buffer in the Speedgoat i receive a uint8 array, that i want to convert to a the corresponding ascii value and then convert the new array into one double.
For example
uint8: [48 46 56 52] -> [0 . 8 4] -> 0.84
Help would be much appreciated!
2 Commenti
Zhengyi Chen
il 11 Apr 2019
You can convert uin8 data into char and use str2double() function to conver the strings in to double data type.
Walter Roberson
il 12 Apr 2019
... Which is the Answer that I posted.
Risposte (3)
José-Luis
il 24 Ott 2012
Somewhat convoluted, depends on whether you can use sprintf() and sscanf():
your_ascii = [48 46 56 52];
your_ascii = your_ascii - '0';
your_string = sprintf('%i',your_ascii);
% your_string = regexprep(your_string,'-','.'); %This could work also, instead of the indexing
your_string(your_string == '-') = '.';
your_val = sscanf(your_string,'%f');
Andrei Bobrov
il 24 Ott 2012
a = uint8([50 48 46 48 48 56 52] );
i0 = a == 46;
a1 = a(~i0)-'0';
out = double(a1)*(10.^(numel(a1)-1:-1:0).')*10^-(find(i0)+1);
Categorie
Scopri di più su String in Centro assistenza e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!