Azzera filtri
Azzera filtri

Conversion from uint8 to ascii to number

19 visualizzazioni (ultimi 30 giorni)
Carl-Johan Elm
Carl-Johan Elm il 16 Ott 2012
Commentato: Walter Roberson il 12 Apr 2019
I am currently working with RS232 serial communication between a Trimble gps and a Speedgoat real time computer in Simulink. From the buffer in the Speedgoat i receive a uint8 array, that i want to convert to a the corresponding ascii value and then convert the new array into one double.
For example
uint8: [48 46 56 52] -> [0 . 8 4] -> 0.84
Help would be much appreciated!
  2 Commenti
Zhengyi Chen
Zhengyi Chen il 11 Apr 2019
You can convert uin8 data into char and use str2double() function to conver the strings in to double data type.
Walter Roberson
Walter Roberson il 12 Apr 2019
... Which is the Answer that I posted.

Accedi per commentare.

Risposte (3)

Walter Roberson
Walter Roberson il 16 Ott 2012
str2double(char(TheArray))
  1 Commento
Carl-Johan Elm
Carl-Johan Elm il 24 Ott 2012
Thanks but you can not use the char() or str2double() command in embedded matlab functions in simulink. =(

Accedi per commentare.


José-Luis
José-Luis il 24 Ott 2012
Somewhat convoluted, depends on whether you can use sprintf() and sscanf():
your_ascii = [48 46 56 52];
your_ascii = your_ascii - '0';
your_string = sprintf('%i',your_ascii);
% your_string = regexprep(your_string,'-','.'); %This could work also, instead of the indexing
your_string(your_string == '-') = '.';
your_val = sscanf(your_string,'%f');

Andrei Bobrov
Andrei Bobrov il 24 Ott 2012
a = uint8([50 48 46 48 48 56 52] );
i0 = a == 46;
a1 = a(~i0)-'0';
out = double(a1)*(10.^(numel(a1)-1:-1:0).')*10^-(find(i0)+1);

Prodotti

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by