How to find and replace the content of an array

Hi guys. Sorry to bother you again, but I am new at Matlab.

I have this timestamp array:

'03/07/2019'

'03/07/2019 00:30:00'

'03/07/2019 01:00:00'

'03/07/2019 01:30:00'

'03/07/2019 02:00:00'

'03/07/2019 02:30:00'

And it goes for 10 days (480 values). The first cell of each day is like '03/07/2019', time is missing. I need to find this kind of cell

and add '00:00:00' to the cell content. So, the first cell should be '03/07/2019 00:00;00' instead of '03/07/2019'.

I applied the function cellfun. The length of the desirable cells is 10. I know I have to find the content of these cells and replace it,

but I am writing a loop. I wonder if there is an easier way to do that.

Thank you for your support!

Answer 1

[Mohammad Sami]

% sometimestamp = {'03/07/2019' '03/07/2019 00:30:00'};

l = cellfun(@length,sometimestamp);
% or
% l = strlength(sometimestamp);
sometimestamp(l==10) = cellfun(@(x)[x ' 00:00:00'],sometimestamp(l==10),'UniformOutput',false);

[JOAO LIMA]

Mohammad Sami , I implemented all the suggestions. ! You guys are great!

Answer 2

[Bhaskar R]

out = cellfun(@(x)datetime(x, 'Format','dd/MM/yyyy HH:mm:ss'), input_cell)

[JOAO LIMA]

Bhaskar R , it worked fine!! Thanks a lot!

Answer 3

[Stephen23]

>> C = {'03/07/2019' '03/07/2019 00:30:00'};
>> X = cellfun('length',C)==10;
>> C(X) = strcat(C(X),' 00:00:00')
C =
 03/07/2019 00:00:00
 03/07/2019 00:30:00