confronting cell with abelians (logic values)
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gabriele fadanelli
il 8 Apr 2020
Commentato: the cyclist
il 8 Apr 2020
I have a question about the way to extract some data from a cell based on some "indices" (in this case I want only to get as an output the "1-associated" values, e.g.:
A={'a' 'b' 'c'; 'd' 'e' 'f';'g' 'h' 'i'}
B=eye(3);
...formula to compare the arrays....
C={'a' '0' '0'; '0' 'e' '0';'0' '0' 'i'}
or
C={'a' nan nan; nan 'e' nan;nan nan 'i'}
I really cannot see the way to easily do it. Thanks
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Ameer Hamza
il 8 Apr 2020
[A{~B}] = deal('0');
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the cyclist
il 8 Apr 2020
A simpler version of this idea is
A(~B) = {'0'}
Caution: this solution overwrites A itself, which you may not want.
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