Is it correct? (dirac delta function)

 Risposta accettata

Walter Roberson
Walter Roberson il 19 Apr 2020

1 voto

no it should be 2*(n==0)
However there is another sense in which dirac(x) should be infinite when x is 0 instead being 1.

Più risposte (1)

You code is correct. Another way is to use built-in kroneckerDelta function.
n = sym(-5:5);
xn = kroneckerDelta(n,-2) - 2*kroneckerDelta(n,0) + kroneckerDelta(n,2);
stem(n, xn, 'b', 'filled')
axis([-10 10 -5 5])

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