Normalization pdf histogram and cdf
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Hi, I am using this code in MATLAB:
histogram(my data,'Normalization','pdf');
after plotting the pdf histogram, the y axis is in a range between 0 to 100. But I need to have the y axis in a range between 0 to 1, because when I plot: (my data, 'Normalization','cdf') the y axis is in range 0 to 1. Please help me to have both "pdf" and "cdf" in a same y axis scale (0 to 1) in one graph. Thank you.
1 Commento
Thi Lan Anh DINH
il 28 Giu 2022
Using 'probability' instead of 'pdf', so that your y-axis will be from 0 to 1.
histogram(my data,'Normalization','probability');
Risposte (2)
Walter Roberson
il 2 Mag 2020
2 voti
You could use ylim() to simply prevent the peak from being drawn.
Or you could increase the bar widths, such as by decreasing the number of bars you ask for.
5 Commenti
Farshad Daraei Ghadikolaei
il 2 Mag 2020
Walter Roberson
il 2 Mag 2020
% 'pdf' Probability density function estimate. The height
% of each bar is, (number of observations in bin)
% / (total number of observations * width of bin).
% The area of each bar is the relative number of
% observations, and the sum of the bar areas is
% less than or equal to 1.
Therefore, pdf is not just fraction of the observations, it is fraction scaled according to width of the bin. If you have a large number of observations in a small enough bin, then the pdf should be greater than 1. If you force the pdf to be less than 1 then you are not displaying pdf.
If you have a histogram pdf going up to 100 then you have some seriously distorted statistics, but it is valid.
It might perhaps make more sense for you to use 'probability' as your normalization rather than pdf.
Farshad Daraei Ghadikolaei
il 2 Mag 2020
Modificato: Farshad Daraei Ghadikolaei
il 2 Mag 2020
Jeff Miller
il 3 Mag 2020
Yes, that is possible. Look at the command 'yyaxis' or (if you have an older version of MATLAB) 'plotyy'.
Farshad Daraei Ghadikolaei
il 3 Mag 2020
Farshad Daraei Ghadikolaei
il 6 Mag 2020
0 voti
3 Commenti
Walter Roberson
il 6 Mag 2020
pdf is Probability Density.
Suppose for example that you had a uniform distribution with "probability" p over 0 to 1/2. Then then the total would be
and that would be p*(1/2 - 0) = p/2 . But the total probability must be 1, so p/2 == 1 which requires that p = 2. But how can "probability" be 2 ? The answer is that what you are integrating is not probability itself but rather "probability density" with it being necessary to adjust by area that the probability distribution occurs over.
Farshad Daraei Ghadikolaei
il 8 Mag 2020
Steven Lord
il 28 Giu 2022
If you look at the description of the Name-Value argument 'Normalization' on the histogram documentation page, the table in that section lists how the bin values are computed.
For probability Normalization, the bin values are the bin counts divided by the number of elements in the input data and so they must all be less than or equal to 1.
For pdf Normalization, the bin values are the probability values (= bin counts divided by number of elements) divided by the bin width. If you have bins of width less than 1 the pdf bin values will be greater than the probability bin values.
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