Unrecognized method, property, or field 'value' for class

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Hi everyone,
I am trying to use a switch in Matlab app designer for a uit converter. However when I code the program to change the items in a drop down menu to change when the switch is flipped, i get this message: 'Unrecognized method, property, or field 'value' for class.' I'm not really sure what this means or how to solve it. I have attatched my code file if you would like to look at it and help me out.
thanks in advance!
  1 Commento
SAI
SAI il 12 Nov 2024
Unrecognized method, property, or field
'P2ditField_4' for class 'app1'.

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Mohammad Sami
Mohammad Sami il 5 Mag 2020
You are using smaller case for value on line 37. just change to upper case as follows.
conversionvalue = app.conversiontypeDropDown.Value;
  3 Commenti
Eric Sargent
Eric Sargent il 9 Dic 2020
Modificato: Eric Sargent il 9 Dic 2020
You have an extra space at the end of "imperial to metric" in the Items property of your switch.
So you're never getting a logical match because when the switch is on "imperial to metric" its actual value is "imperial to metric " with that extra space at the end and thus will never be equal to your hardcoded comparitive value of "imperial to metric".
Instead, I'd propose you try to match the value to the actual Items.
For example, instead of:
function SwitchValueChanged(app, event)
value = app.Switch.Value;
udc = app.conversiontypeDropDown.Value;
if strcmpi(udc, 'temperature') && strcmpi(value, 'imperial to metric')
app.unitsDropDown.Items = {'fahrenheit to celcius'};
end
end
You could consider:
function SwitchValueChanged(app, event)
value = string(app.Switch.Value);
udc = string(app.conversiontypeDropDown.Value);
if udc == "temperature" && value == string(app.Switch.Items(2))
app.unitsDropDown.Items = "fahrenheit to celcius";
end
end
That way you will always be comparing a value to a possible solution rather than a hardcoded string.

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