Problem 44951. Verify Law of Large Numbers

function dice_diff = loln(N)
add = 0; mean = 0; mean1 = 0;add1=0;
for c=1:1*exp(8)
    num = randi(N);
    add = add + num;
end
mean = add/(1*exp(8))
for c=1:N
    add1=add1+c;
end
mean1=add1/N
    dice_diff = mean-mean1
end

The code works fine but the result is not as expected. Could anyone tell the reason?

Answer 1

[Walter Roberson]

If you want 2980 iterations then why not use 2980 instead of exp(8) ?

mean = add/(1*exp(8))

Incorrect. You do an integer number of iterations, 2980, but you divide by exp(8) which is about 2980.96 so you get the wrong mean() value. You sould be dividing by the number of iterations you do. Or you should use mean()

[Tavish Pattanayak]

Changed exp(8) to 2980 but the output still remains the same.

[Walter Roberson]

Well, at this point the question should be what result you expect, and how does your result differ from what you expected?

[Tavish Pattanayak]

So I am doing this on MATLAB Cody and it shows that my code works but the output differs hence overall wrong code.

[Walter Roberson]

The question requires that you simulate 1e8 rolls, not 1*exp(8) . 1e8 is 1*10^8

[Tavish Pattanayak]

Yes it worked. Thank you so much!