Azzera filtri
Azzera filtri

i need to make this function work without puting inputs all i need to call it put the z and the n and the function will give me the answer

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function y=int1(z,n)
syms x n m z a;
for m=1:n;
z=int(z)
end
sorry i mean this one

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Rik
Rik il 7 Mag 2020
Why are you defining everything as symbolic? Why aren't you storing any output? Why are you overwriting your inputs with the syms function? The code below is one of the possible ways to answer these questions.
clc
clearvars
syms z
mySymFun= 3*z^2-9;
n=4;
y=int1(mySymFun,n);
clc,disp(y)
function z=int1(z,n)
%integrate z for n times
for m=1:n
z=int(z);
end
end
  11 Commenti
Rik
Rik il 7 Mag 2020
Glad to be of help.
If you feel my answer solved your issue, please consider marking it as accepted answer.

Accedi per commentare.

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